4x2-160-1296=0

Solution for 4x2-160-1296=0 equation:

4x^2-160-1296=0

We add all the numbers together, and all the variables

4x^2-1456=0

a = 4; b = 0; c = -1456;
Δ = b2-4ac
Δ = 02-4·4·(-1456)
Δ = 23296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{23296}=\sqrt{256*91}=\sqrt{256}*\sqrt{91}=16\sqrt{91}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{91}}{2*4}=\frac{0-16\sqrt{91}}{8}
=-\frac{16\sqrt{91}}{8}
=-2\sqrt{91}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{91}}{2*4}=\frac{0+16\sqrt{91}}{8}
=\frac{16\sqrt{91}}{8}
=2\sqrt{91}
$