4x2-13x=12

Solution for 4x2-13x=12 equation:

4x^2-13x=12

We move all terms to the left:

4x^2-13x-(12)=0

a = 4; b = -13; c = -12;
Δ = b2-4ac
Δ = -132-4·4·(-12)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-19}{2*4}=\frac{-6}{8}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+19}{2*4}=\frac{32}{8}
=4
$