If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2+5x-3=0
a = 4; b = 5; c = -3;
Δ = b2-4ac
Δ = 52-4·4·(-3)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{73}}{2*4}=\frac{-5-\sqrt{73}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{73}}{2*4}=\frac{-5+\sqrt{73}}{8} $
| -5+5(n-7)=40+50 | | (x+7)^{2}=49 | | 4x+25=32 | | 1/3(c+4)=12 | | 15x-27=-12-4 | | 15x-27=-12-5x | | 6-(4x)=-2 | | 8=4+2g= | | 6-(4x=-2 | | −4x+4=32 | | 138=m*8+90 | | -5(x-4)+2=14-3x | | x/3+15=20 | | (x+81)+(121+x)=180 | | y=3-76 | | 2k^2+4k+10=0 | | -10x+16=3 | | (x-22)+x=180 | | -72+36l=360 | | 11a-6=2 | | 5^(2x-4)=25 | | 35=m*5+10 | | 4(1.5+y)=6+y | | 12x-4+0.25x=45 | | 7x+2=-4x9.7 | | 2(3x-1)-7x=6-4x | | 4e-10=e+5 | | 24+4x=3x+52 | | -4(m÷3)=24 | | 5^(5x)=125^(x+1) | | 2 | | 4+8x=3x+39 |