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4x^2+56=168
We move all terms to the left:
4x^2+56-(168)=0
We add all the numbers together, and all the variables
4x^2-112=0
a = 4; b = 0; c = -112;
Δ = b2-4ac
Δ = 02-4·4·(-112)
Δ = 1792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1792}=\sqrt{256*7}=\sqrt{256}*\sqrt{7}=16\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{7}}{2*4}=\frac{0-16\sqrt{7}}{8} =-\frac{16\sqrt{7}}{8} =-2\sqrt{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{7}}{2*4}=\frac{0+16\sqrt{7}}{8} =\frac{16\sqrt{7}}{8} =2\sqrt{7} $
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