4x2+35=3675

Solution for 4x2+35=3675 equation:

4x^2+35=3675

We move all terms to the left:

4x^2+35-(3675)=0

We add all the numbers together, and all the variables

4x^2-3640=0

a = 4; b = 0; c = -3640;
Δ = b2-4ac
Δ = 02-4·4·(-3640)
Δ = 58240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{58240}=\sqrt{64*910}=\sqrt{64}*\sqrt{910}=8\sqrt{910}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{910}}{2*4}=\frac{0-8\sqrt{910}}{8}
=-\frac{8\sqrt{910}}{8}
=-\sqrt{910}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{910}}{2*4}=\frac{0+8\sqrt{910}}{8}
=\frac{8\sqrt{910}}{8}
=\sqrt{910}
$