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4x^2+34x+42=0
a = 4; b = 34; c = +42;
Δ = b2-4ac
Δ = 342-4·4·42
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-22}{2*4}=\frac{-56}{8} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+22}{2*4}=\frac{-12}{8} =-1+1/2 $
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