4x2+2=63

Solution for 4x2+2=63 equation:

4x^2+2=63

We move all terms to the left:

4x^2+2-(63)=0

We add all the numbers together, and all the variables

4x^2-61=0

a = 4; b = 0; c = -61;
Δ = b2-4ac
Δ = 02-4·4·(-61)
Δ = 976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{976}=\sqrt{16*61}=\sqrt{16}*\sqrt{61}=4\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{61}}{2*4}=\frac{0-4\sqrt{61}}{8}
=-\frac{4\sqrt{61}}{8}
=-\frac{\sqrt{61}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{61}}{2*4}=\frac{0+4\sqrt{61}}{8}
=\frac{4\sqrt{61}}{8}
=\frac{\sqrt{61}}{2}
$