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4x^2+24x=-36
We move all terms to the left:
4x^2+24x-(-36)=0
We add all the numbers together, and all the variables
4x^2+24x+36=0
a = 4; b = 24; c = +36;
Δ = b2-4ac
Δ = 242-4·4·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-24}{8}=-3$
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