4x2+23x=6

Solution for 4x2+23x=6 equation:

4x^2+23x=6

We move all terms to the left:

4x^2+23x-(6)=0

a = 4; b = 23; c = -6;
Δ = b2-4ac
Δ = 232-4·4·(-6)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-25}{2*4}=\frac{-48}{8}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+25}{2*4}=\frac{2}{8}
=1/4
$