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4x^2+20x=-45
We move all terms to the left:
4x^2+20x-(-45)=0
We add all the numbers together, and all the variables
4x^2+20x+45=0
a = 4; b = 20; c = +45;
Δ = b2-4ac
Δ = 202-4·4·45
Δ = -320
Delta is less than zero, so there is no solution for the equation
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