4x2+16x-24=156

Solution for 4x2+16x-24=156 equation:

4x^2+16x-24=156

We move all terms to the left:

4x^2+16x-24-(156)=0

We add all the numbers together, and all the variables

4x^2+16x-180=0

a = 4; b = 16; c = -180;
Δ = b2-4ac
Δ = 162-4·4·(-180)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-56}{2*4}=\frac{-72}{8}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+56}{2*4}=\frac{40}{8}
=5
$