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4x^2+14=47.75
We move all terms to the left:
4x^2+14-(47.75)=0
We add all the numbers together, and all the variables
4x^2-33.75=0
a = 4; b = 0; c = -33.75;
Δ = b2-4ac
Δ = 02-4·4·(-33.75)
Δ = 540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{540}=\sqrt{36*15}=\sqrt{36}*\sqrt{15}=6\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{15}}{2*4}=\frac{0-6\sqrt{15}}{8} =-\frac{6\sqrt{15}}{8} =-\frac{3\sqrt{15}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{15}}{2*4}=\frac{0+6\sqrt{15}}{8} =\frac{6\sqrt{15}}{8} =\frac{3\sqrt{15}}{4} $
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