If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2+12x+2=0
a = 4; b = 12; c = +2;
Δ = b2-4ac
Δ = 122-4·4·2
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{7}}{2*4}=\frac{-12-4\sqrt{7}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{7}}{2*4}=\frac{-12+4\sqrt{7}}{8} $
| 30.6+w=21.75+16.6 | | -4(3/2x)-1=0 | | -4(3/2x)=0 | | 7p+8=4.5 | | 1/4(13y-3)1/16(12y+17)= | | 7x-9x=3x+1 | | -10u-2=-9u | | 3/4w=11.25 | | -10u−2=-9u | | 0=2p-2p | | 6t+18=6-6t | | -7+3y=3y | | 8h=10+8h | | 7y+7=6y+8 | | w+(-322)=-728 | | |5x-8|=|2x-7| | | 4x-(-21-7x)=-1 | | 10-3b+3=-1+3b | | 2(4r-4)-3(r-7)= | | 9x^2+2x-81=0 | | 0.02(y-8)+0.16=0.08y-1 | | 0.15x-15=12.75 | | (2x)^2=3.4x10^-12 | | “x/3=(2x+3)/7” | | 2x^2-36x+18=0 | | 5x(x+7)=8x+56 | | 4x(x+1)=4-11x | | 180=(2x+1)+x | | X+y/3=5y=7 | | 2x^2-36+18=0 | | H=3x+2 | | 5+x/9=31 |