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4x^2+1.52x-7.6=0
a = 4; b = 1.52; c = -7.6;
Δ = b2-4ac
Δ = 1.522-4·4·(-7.6)
Δ = 123.9104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.52)-\sqrt{123.9104}}{2*4}=\frac{-1.52-\sqrt{123.9104}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.52)+\sqrt{123.9104}}{2*4}=\frac{-1.52+\sqrt{123.9104}}{8} $
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