4x2+-4x+-5=8x+6

Solution for 4x2+-4x+-5=8x+6 equation:

4x^2+-4x+-5=8x+6

We move all terms to the left:

4x^2+-4x+-5-(8x+6)=0

We add all the numbers together, and all the variables

4x^2-4x-(8x+6)=0

We get rid of parentheses

4x^2-4x-8x-6=0

We add all the numbers together, and all the variables

4x^2-12x-6=0

a = 4; b = -12; c = -6;
Δ = b2-4ac
Δ = -122-4·4·(-6)
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{15}}{2*4}=\frac{12-4\sqrt{15}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{15}}{2*4}=\frac{12+4\sqrt{15}}{8}
$