4x/5x=(7x+8)/(9x-10)

Solution for 4x/5x=(7x+8)/(9x-10) equation:

4x/5x=(7x+8)/(9x-10)

We move all terms to the left:

4x/5x-((7x+8)/(9x-10))=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: (9x-10))!=0

x∈R


We calculate fractions


(-4x^2)/(-5x^2)+(-((7x+8)*5x)/(-5x^2)=0


We calculate terms in parentheses: +(-((7x+8)*5x)/(-5x^2), so:

-((7x+8)*5x)/(-5x^2

We multiply all the terms by the denominator


-((7x+8)*5x)


We calculate terms in parentheses: -((7x+8)*5x), so:

(7x+8)*5x

We multiply parentheses

35x^2+40x

Back to the equation:

-(35x^2+40x)


We get rid of parentheses

-35x^2-40x

Back to the equation:

+(-35x^2-40x)


We get rid of parentheses

(-4x^2)/(-5x^2)-35x^2-40x=0

We multiply all the terms by the denominator


(-4x^2)-35x^2*(-5x^2)-40x*(-5x^2)=0

We multiply parentheses

(-4x^2)-35x^2*(-5x^2)+200x^3=0

We get rid of parentheses

-4x^2-35x^2*(-5x^2)+200x^3=0

We do not support expression: x^3