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x in (-oo:+oo)
(4*x)/5-((2*x)/3) = (2*x)/15 // - (2*x)/15
(4*x)/5-((2*x)/3)-((2*x)/15) = 0
(4*x)/5+(-2/3)*x+(-2/15)*x = 0
0 = 0
x należy do R
x in (-oo:+oo)
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