4x/3+9/x=7

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Solution for 4x/3+9/x=7 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4*x)/3+9/x = 7 // - 7

(4*x)/3+9/x-7 = 0

4/3*x^1+9*x^-1-7*x^0 = 0

(4/3*x^2-7*x^1+9*x^0)/(x^1) = 0 // * x^2

x^1*(4/3*x^2-7*x^1+9*x^0) = 0

x^1

(4/3)*x^2-7*x+9 = 0

(4/3)*x^2-7*x+9 = 0

DELTA = (-7)^2-(4*9*(4/3))

DELTA = 1

DELTA > 0

x = (1^(1/2)+7)/(2*(4/3)) or x = (7-1^(1/2))/(2*(4/3))

x = 3 or x = 9/4

x in { 9/4, 3} 

x in { 9/4, 3 }

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