4x/(x+2)=8-8/(x+2)

Solution for 4x/(x+2)=8-8/(x+2) equation:

4x/(x+2)=8-8/(x+2)

We move all terms to the left:

4x/(x+2)-(8-8/(x+2))=0


Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R



Domain of the equation: (x+2))!=0

x∈R


We calculate fractions


12x^2/((x+2)*(x+2)))+(-(-8*(x+10))/((x+2)*(x+2)))=0


We calculate terms in parentheses: -(-8*(x+10))/((x+2)*(x+2))), so:

-8*(x+10))/((x+2)*(x+2))

We multiply all the terms by the denominator


-8*(x+10))

We multiply parentheses

-8x-

We add all the numbers together, and all the variables

-8x

Back to the equation:

-(-8x)


We get rid of parentheses

12x^2/((x+2)*(x+2)))+(+8x=0

We multiply all the terms by the denominator


12x^2+8x*((x+2)*(x+2)))+(=0