4x/(33+x)=1/3

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Solution for 4x/(33+x)=1/3 equation: 


D( x )

x+33 = 0

x+33 = 0

x+33 = 0

x+33 = 0 // - 33

x = -33

x in (-oo:-33) U (-33:+oo)

(4*x)/(x+33) = 1/3 // - 1/3

(4*x)/(x+33)-(1/3) = 0

(4*x)/(x+33)-1/3 = 0

(3*4*x)/(3*(x+33))+(-1*(x+33))/(3*(x+33)) = 0

3*4*x-1*(x+33) = 0

11*x-33 = 0

(11*x-33)/(3*(x+33)) = 0

(11*x-33)/(3*(x+33)) = 0 // * 3*(x+33)

11*x-33 = 0

11*x-33 = 0 // + 33

11*x = 33 // : 11

x = 33/11

x = 3

x = 3

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