4x-8x+68=3x+40

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Solution for 4x-8x+68=3x+40 equation: 



4x-8x+68=3x+40

We move all terms to the left:

4x-8x+68-(3x+40)=0

We add all the numbers together, and all the variables

-4x-(3x+40)+68=0

We get rid of parentheses

-4x-3x-40+68=0

We add all the numbers together, and all the variables

-7x+28=0

We move all terms containing x to the left, all other terms to the right

-7x=-28

x=-28/-7

x=+4

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