4x-8=2x(2x-2)

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Solution for 4x-8=2x(2x-2) equation: 



4x-8=2x(2x-2)

We move all terms to the left:

4x-8-(2x(2x-2))=0



We calculate terms in parentheses: -(2x(2x-2)), so:

2x(2x-2)

We multiply parentheses

4x^2-4x

Back to the equation:

-(4x^2-4x)



We get rid of parentheses

-4x^2+4x+4x-8=0

We add all the numbers together, and all the variables

-4x^2+8x-8=0

a = -4; b = 8; c = -8;
Δ = b2-4ac
Δ = 82-4·(-4)·(-8)
Δ = -64
Delta is less than zero, so there is no solution for the equation

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