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4x-7/3x=1
We move all terms to the left:
4x-7/3x-(1)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
4x*3x-1*3x-7=0
Wy multiply elements
12x^2-3x-7=0
a = 12; b = -3; c = -7;
Δ = b2-4ac
Δ = -32-4·12·(-7)
Δ = 345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{345}}{2*12}=\frac{3-\sqrt{345}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{345}}{2*12}=\frac{3+\sqrt{345}}{24} $
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