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4x-7/3x-1=-2
We move all terms to the left:
4x-7/3x-1-(-2)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
4x-7/3x+1=0
We multiply all the terms by the denominator
4x*3x+1*3x-7=0
Wy multiply elements
12x^2+3x-7=0
a = 12; b = 3; c = -7;
Δ = b2-4ac
Δ = 32-4·12·(-7)
Δ = 345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{345}}{2*12}=\frac{-3-\sqrt{345}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{345}}{2*12}=\frac{-3+\sqrt{345}}{24} $
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