4x-7/2x-5+9x+7/3x+1=5

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Solution for 4x-7/2x-5+9x+7/3x+1=5 equation:



4x-7/2x-5+9x+7/3x+1=5
We move all terms to the left:
4x-7/2x-5+9x+7/3x+1-(5)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
13x-7/2x+7/3x-9=0
We calculate fractions
13x+(-21x)/6x^2+14x/6x^2-9=0
We multiply all the terms by the denominator
13x*6x^2+(-21x)+14x-9*6x^2=0
We add all the numbers together, and all the variables
14x+13x*6x^2+(-21x)-9*6x^2=0
Wy multiply elements
78x^3-54x^2+14x+(-21x)=0
We get rid of parentheses
78x^3-54x^2+14x-21x=0
We do not support expression: x^3

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