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4x-5=1/5x
We move all terms to the left:
4x-5-(1/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4x-(+1/5x)-5=0
We get rid of parentheses
4x-1/5x-5=0
We multiply all the terms by the denominator
4x*5x-5*5x-1=0
Wy multiply elements
20x^2-25x-1=0
a = 20; b = -25; c = -1;
Δ = b2-4ac
Δ = -252-4·20·(-1)
Δ = 705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{705}}{2*20}=\frac{25-\sqrt{705}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{705}}{2*20}=\frac{25+\sqrt{705}}{40} $
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