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4x-5/6x-7=0
Domain of the equation: 6x!=0We multiply all the terms by the denominator
x!=0/6
x!=0
x∈R
4x*6x-7*6x-5=0
Wy multiply elements
24x^2-42x-5=0
a = 24; b = -42; c = -5;
Δ = b2-4ac
Δ = -422-4·24·(-5)
Δ = 2244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2244}=\sqrt{4*561}=\sqrt{4}*\sqrt{561}=2\sqrt{561}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-2\sqrt{561}}{2*24}=\frac{42-2\sqrt{561}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+2\sqrt{561}}{2*24}=\frac{42+2\sqrt{561}}{48} $
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