4x-5/12x+4+3x-1/3x+1=x

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Solution for 4x-5/12x+4+3x-1/3x+1=x equation: 



4x-5/12x+4+3x-1/3x+1=x

We move all terms to the left:

4x-5/12x+4+3x-1/3x+1-(x)=0



Domain of the equation: 12x!=0

x!=0/12

x!=0

x∈R





Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We add all the numbers together, and all the variables

6x-5/12x-1/3x+5=0

We calculate fractions


6x+(-15x)/36x^2+(-12x)/36x^2+5=0

We multiply all the terms by the denominator


6x*36x^2+(-15x)+(-12x)+5*36x^2=0

Wy multiply elements

216x^3+180x^2+(-15x)+(-12x)=0

We get rid of parentheses

216x^3+180x^2-15x-12x=0

We do not support expression: x^3

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