4x-5/1-6x=x+10/x-6

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Solution for 4x-5/1-6x=x+10/x-6 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x-(6*x)-(5/1) = x+10/x-6 // - x+10/x-6

4*x-(6*x)-x-(10/x)-(5/1)+6 = 0

4*x-6*x-x-10*x^-1-5+6 = 0

1*x^0-3*x^1-10*x^-1 = 0

(1*x^1-3*x^2-10*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^1-3*x^2-10*x^0) = 0

x^1

x-3*x^2-10 = 0

x-3*x^2-10 = 0

DELTA = 1^2-(-10*(-3)*4)

DELTA = -119

DELTA < 0

x in { } 

x belongs to the empty set

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