4x-5(x-2)=3x+(-12)

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Solution for 4x-5(x-2)=3x+(-12) equation: 



4x-5(x-2)=3x+(-12)

We move all terms to the left:

4x-5(x-2)-(3x+(-12))=0

We multiply parentheses

4x-5x-(3x+(-12))+10=0



We calculate terms in parentheses: -(3x+(-12)), so:

3x+(-12)

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

-1x-(3x-12)+10=0

We get rid of parentheses

-1x-3x+12+10=0

We add all the numbers together, and all the variables

-4x+22=0

We move all terms containing x to the left, all other terms to the right

-4x=-22

x=-22/-4

x=5+1/2

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