4x-4/x-1

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Solution for 4x-4/x-1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x-(4/x)-1 = 0

4*x-4*x^-1-1 = 0

4*x^1-4*x^-1-1*x^0 = 0

(4*x^2-1*x^1-4*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^2-1*x^1-4*x^0) = 0

x^1

4*x^2-x-4 = 0

4*x^2-x-4 = 0

DELTA = (-1)^2-(-4*4*4)

DELTA = 65

DELTA > 0

x = (65^(1/2)+1)/(2*4) or x = (1-65^(1/2))/(2*4)

x = (65^(1/2)+1)/8 or x = (1-65^(1/2))/8

x in { (1-65^(1/2))/8, (65^(1/2)+1)/8} 

x in { (1-65^(1/2))/8, (65^(1/2)+1)/8 }

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