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4x-3x+1=-5(x-1)+2(3x-2)
We move all terms to the left:
4x-3x+1-(-5(x-1)+2(3x-2))=0
We add all the numbers together, and all the variables
x-(-5(x-1)+2(3x-2))+1=0
We calculate terms in parentheses: -(-5(x-1)+2(3x-2)), so:We get rid of parentheses
-5(x-1)+2(3x-2)
We multiply parentheses
-5x+6x+5-4
We add all the numbers together, and all the variables
x+1
Back to the equation:
-(x+1)
x-x-1+1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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