4x-3=6(2+1/2x)

Solution for 4x-3=6(2+1/2x) equation:

4x-3=6(2+1/2x)

We move all terms to the left:

4x-3-(6(2+1/2x))=0


Domain of the equation: 2x))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4x-(6(1/2x+2))-3=0

We multiply all the terms by the denominator


4x*2x-3*2x+2))-(6(1+2))=0

We add all the numbers together, and all the variables

4x*2x-3*2x+2))-(63)=0

We add all the numbers together, and all the variables

4x*2x-3*2x=0

Wy multiply elements

8x^2-6x=0

a = 8; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·8·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*8}=\frac{0}{16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*8}=\frac{12}{16}
=3/4
$