If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
4*x-3 = (1/2)*(4*x-10) // - (1/2)*(4*x-10)
4*x-((1/2)*(4*x-10))-3 = 0
(-1/2)*(4*x-10)+4*x-3 = 0
4*x-1/2*(4*x-10)-3 = 0
4*x-1/2*(4*x-10)-3 = 0
2*x-3+5 = 0
2*x+2 = 0
2*x+2 = 0
2*x+2 = 0 // - 2
2*x = -2 // : 2
x = -2/2
x = -1
x = -1
| 3-3g=6 | | =2abcd+3acbd-12dcba | | 24-2x+6x=-2(-5x+9) | | 36=-9-3p | | -39-11y+19=-23y+50+7y | | -2x+1=3x-34 | | 8(x+3)=2x+16+8x | | f-8/9=5/9 | | 3-4x=-6x+15 | | 6(r-1)=r-20+3r | | 12x-11=3x+7 | | (9+x)5=935 | | 2x^4-5x-3=0 | | A=(s+k)hfors | | -10=2(1-2P) | | (8²/2²).4³ | | -x+5(x+6)=4x-30 | | (8²/2²)x4³ | | 5x+2=24+3x | | 2x/3/25 | | =4x-4x-5y+6y | | 3v^2+v-2v^2= | | 6-5x-15=4+x+1 | | 20x-6=6x^2 | | X:2.4=19.2/8.3 | | -3(6k-9)=-27 | | -2x-55=-8x-7 | | 10-5x=-4x+8 | | 4x=(96+3x) | | K-8+8k=2(k+3) | | (1)/(3)f(x) | | ln((x^2)+1)=ln(x) |