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4x-3/2x=15
We move all terms to the left:
4x-3/2x-(15)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
4x*2x-15*2x-3=0
Wy multiply elements
8x^2-30x-3=0
a = 8; b = -30; c = -3;
Δ = b2-4ac
Δ = -302-4·8·(-3)
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{249}}{2*8}=\frac{30-2\sqrt{249}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{249}}{2*8}=\frac{30+2\sqrt{249}}{16} $
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