4x-3(x+1)=-3x+4(x+3)+5x

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Solution for 4x-3(x+1)=-3x+4(x+3)+5x equation: 



4x-3(x+1)=-3x+4(x+3)+5x

We move all terms to the left:

4x-3(x+1)-(-3x+4(x+3)+5x)=0

We multiply parentheses

4x-3x-(-3x+4(x+3)+5x)-3=0



We calculate terms in parentheses: -(-3x+4(x+3)+5x), so:

-3x+4(x+3)+5x

We add all the numbers together, and all the variables

2x+4(x+3)

We multiply parentheses

2x+4x+12

We add all the numbers together, and all the variables

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

x-(6x+12)-3=0

We get rid of parentheses

x-6x-12-3=0

We add all the numbers together, and all the variables

-5x-15=0

We move all terms containing x to the left, all other terms to the right

-5x=15

x=15/-5

x=-3

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