4x-3(6x-5)=7(x+1)

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Solution for 4x-3(6x-5)=7(x+1) equation: 



4x-3(6x-5)=7(x+1)

We move all terms to the left:

4x-3(6x-5)-(7(x+1))=0

We multiply parentheses

4x-18x-(7(x+1))+15=0



We calculate terms in parentheses: -(7(x+1)), so:

7(x+1)

We multiply parentheses

7x+7

Back to the equation:

-(7x+7)



We add all the numbers together, and all the variables

-14x-(7x+7)+15=0

We get rid of parentheses

-14x-7x-7+15=0

We add all the numbers together, and all the variables

-21x+8=0

We move all terms containing x to the left, all other terms to the right

-21x=-8

x=-8/-21

x=8/21

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