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4x-3(3-5x)=2(3x+5)
We move all terms to the left:
4x-3(3-5x)-(2(3x+5))=0
We add all the numbers together, and all the variables
4x-3(-5x+3)-(2(3x+5))=0
We multiply parentheses
4x+15x-(2(3x+5))-9=0
We calculate terms in parentheses: -(2(3x+5)), so:We add all the numbers together, and all the variables
2(3x+5)
We multiply parentheses
6x+10
Back to the equation:
-(6x+10)
19x-(6x+10)-9=0
We get rid of parentheses
19x-6x-10-9=0
We add all the numbers together, and all the variables
13x-19=0
We move all terms containing x to the left, all other terms to the right
13x=19
x=19/13
x=1+6/13
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