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4x-2x(x-5)=-4+5x+2
We move all terms to the left:
4x-2x(x-5)-(-4+5x+2)=0
We add all the numbers together, and all the variables
4x-2x(x-5)-(5x-2)=0
We multiply parentheses
-2x^2+4x+10x-(5x-2)=0
We get rid of parentheses
-2x^2+4x+10x-5x+2=0
We add all the numbers together, and all the variables
-2x^2+9x+2=0
a = -2; b = 9; c = +2;
Δ = b2-4ac
Δ = 92-4·(-2)·2
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{97}}{2*-2}=\frac{-9-\sqrt{97}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{97}}{2*-2}=\frac{-9+\sqrt{97}}{-4} $
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