4x-2=1/2x-5

Solution for 4x-2=1/2x-5 equation:

4x-2=1/2x-5

We move all terms to the left:

4x-2-(1/2x-5)=0


Domain of the equation: 2x-5)!=0

x∈R


We get rid of parentheses

4x-1/2x+5-2=0

We multiply all the terms by the denominator


4x*2x+5*2x-2*2x-1=0

Wy multiply elements

8x^2+10x-4x-1=0

We add all the numbers together, and all the variables

8x^2+6x-1=0

a = 8; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·8·(-1)
Δ = 68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{68}=\sqrt{4*17}=\sqrt{4}*\sqrt{17}=2\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{17}}{2*8}=\frac{-6-2\sqrt{17}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{17}}{2*8}=\frac{-6+2\sqrt{17}}{16}
$