4x-20=(4x-8)/12

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Solution for 4x-20=(4x-8)/12 equation: 



4x-20=(4x-8)/12

We move all terms to the left:

4x-20-((4x-8)/12)=0

We multiply all the terms by the denominator


4x*12)-((4x-8)-20*12)=0

We add all the numbers together, and all the variables

4x*12)-((4x-8)=0

Wy multiply elements

48x^2=0

a = 48; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·48·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{96}=0$

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