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4x-2/3x+14=180
We move all terms to the left:
4x-2/3x+14-(180)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
4x-2/3x-166=0
We multiply all the terms by the denominator
4x*3x-166*3x-2=0
Wy multiply elements
12x^2-498x-2=0
a = 12; b = -498; c = -2;
Δ = b2-4ac
Δ = -4982-4·12·(-2)
Δ = 248100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{248100}=\sqrt{100*2481}=\sqrt{100}*\sqrt{2481}=10\sqrt{2481}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-498)-10\sqrt{2481}}{2*12}=\frac{498-10\sqrt{2481}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-498)+10\sqrt{2481}}{2*12}=\frac{498+10\sqrt{2481}}{24} $
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