4x-2(x-8)=2(x+1)+4

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Solution for 4x-2(x-8)=2(x+1)+4 equation: 



4x-2(x-8)=2(x+1)+4

We move all terms to the left:

4x-2(x-8)-(2(x+1)+4)=0

We multiply parentheses

4x-2x-(2(x+1)+4)+16=0



We calculate terms in parentheses: -(2(x+1)+4), so:

2(x+1)+4

We multiply parentheses

2x+2+4

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

2x-(2x+6)+16=0

We get rid of parentheses

2x-2x-6+16=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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