4x-2(x-4)=-9+4x+13

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Solution for 4x-2(x-4)=-9+4x+13 equation: 



4x-2(x-4)=-9+4x+13

We move all terms to the left:

4x-2(x-4)-(-9+4x+13)=0

We add all the numbers together, and all the variables

4x-2(x-4)-(4x+4)=0

We multiply parentheses

4x-2x-(4x+4)+8=0

We get rid of parentheses

4x-2x-4x-4+8=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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