4x-2(x-4)=-8+5x+10

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Solution for 4x-2(x-4)=-8+5x+10 equation: 



4x-2(x-4)=-8+5x+10

We move all terms to the left:

4x-2(x-4)-(-8+5x+10)=0

We add all the numbers together, and all the variables

4x-2(x-4)-(5x+2)=0

We multiply parentheses

4x-2x-(5x+2)+8=0

We get rid of parentheses

4x-2x-5x-2+8=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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