4x-2(x-3)=2(x+1)+8

Solution for 4x-2(x-3)=2(x+1)+8 equation:

Simplifying
4x + -2(x + -3) = 2(x + 1) + 8

Reorder the terms:
4x + -2(-3 + x) = 2(x + 1) + 8
4x + (-3 * -2 + x * -2) = 2(x + 1) + 8
4x + (6 + -2x) = 2(x + 1) + 8

Reorder the terms:
6 + 4x + -2x = 2(x + 1) + 8

Combine like terms: 4x + -2x = 2x
6 + 2x = 2(x + 1) + 8

Reorder the terms:
6 + 2x = 2(1 + x) + 8
6 + 2x = (1 * 2 + x * 2) + 8
6 + 2x = (2 + 2x) + 8

Reorder the terms:
6 + 2x = 2 + 8 + 2x

Combine like terms: 2 + 8 = 10
6 + 2x = 10 + 2x

Add '-2x' to each side of the equation.
6 + 2x + -2x = 10 + 2x + -2x

Combine like terms: 2x + -2x = 0
6 + 0 = 10 + 2x + -2x
6 = 10 + 2x + -2x

Combine like terms: 2x + -2x = 0
6 = 10 + 0
6 = 10

Solving
6 = 10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.