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4x-2(3-4x)=5(x-5)-9
We move all terms to the left:
4x-2(3-4x)-(5(x-5)-9)=0
We add all the numbers together, and all the variables
4x-2(-4x+3)-(5(x-5)-9)=0
We multiply parentheses
4x+8x-(5(x-5)-9)-6=0
We calculate terms in parentheses: -(5(x-5)-9), so:We add all the numbers together, and all the variables
5(x-5)-9
We multiply parentheses
5x-25-9
We add all the numbers together, and all the variables
5x-34
Back to the equation:
-(5x-34)
12x-(5x-34)-6=0
We get rid of parentheses
12x-5x+34-6=0
We add all the numbers together, and all the variables
7x+28=0
We move all terms containing x to the left, all other terms to the right
7x=-28
x=-28/7
x=-4
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