4x-2(3-4x)=3(x-4)-48

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Solution for 4x-2(3-4x)=3(x-4)-48 equation: 



4x-2(3-4x)=3(x-4)-48

We move all terms to the left:

4x-2(3-4x)-(3(x-4)-48)=0

We add all the numbers together, and all the variables

4x-2(-4x+3)-(3(x-4)-48)=0

We multiply parentheses

4x+8x-(3(x-4)-48)-6=0



We calculate terms in parentheses: -(3(x-4)-48), so:

3(x-4)-48

We multiply parentheses

3x-12-48

We add all the numbers together, and all the variables

3x-60

Back to the equation:

-(3x-60)



We add all the numbers together, and all the variables

12x-(3x-60)-6=0

We get rid of parentheses

12x-3x+60-6=0

We add all the numbers together, and all the variables

9x+54=0

We move all terms containing x to the left, all other terms to the right

9x=-54

x=-54/9

x=-6

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