4x-2(2x-8)=5(2x-7)+9x

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Solution for 4x-2(2x-8)=5(2x-7)+9x equation: 



4x-2(2x-8)=5(2x-7)+9x

We move all terms to the left:

4x-2(2x-8)-(5(2x-7)+9x)=0

We multiply parentheses

4x-4x-(5(2x-7)+9x)+16=0



We calculate terms in parentheses: -(5(2x-7)+9x), so:

5(2x-7)+9x

We add all the numbers together, and all the variables

9x+5(2x-7)

We multiply parentheses

9x+10x-35

We add all the numbers together, and all the variables

19x-35

Back to the equation:

-(19x-35)



We add all the numbers together, and all the variables

-(19x-35)+16=0

We get rid of parentheses

-19x+35+16=0

We add all the numbers together, and all the variables

-19x+51=0

We move all terms containing x to the left, all other terms to the right

-19x=-51

x=-51/-19

x=2+13/19

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