4x-2(2-3x)=3(x-4)-6

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Solution for 4x-2(2-3x)=3(x-4)-6 equation: 



4x-2(2-3x)=3(x-4)-6

We move all terms to the left:

4x-2(2-3x)-(3(x-4)-6)=0

We add all the numbers together, and all the variables

4x-2(-3x+2)-(3(x-4)-6)=0

We multiply parentheses

4x+6x-(3(x-4)-6)-4=0



We calculate terms in parentheses: -(3(x-4)-6), so:

3(x-4)-6

We multiply parentheses

3x-12-6

We add all the numbers together, and all the variables

3x-18

Back to the equation:

-(3x-18)



We add all the numbers together, and all the variables

10x-(3x-18)-4=0

We get rid of parentheses

10x-3x+18-4=0

We add all the numbers together, and all the variables

7x+14=0

We move all terms containing x to the left, all other terms to the right

7x=-14

x=-14/7

x=-2

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